周昶 发表于 2007-10-12 11:03:04

[讨论]一道初中的方程题引起的思考

<p><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: &quot;&quot;; mso-hansi-font-family: &quot;&quot;; mso-bidi-font-family: &quot;&quot;; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">一轮船沿河航行与相距</span><span lang="EN-US" style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">48</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: &quot;&quot;; mso-hansi-font-family: &quot;&quot;; mso-bidi-font-family: &quot;&quot;; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">千米的码头间。往返一次需要</span><span lang="EN-US" style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">10</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: &quot;&quot;; mso-hansi-font-family: &quot;&quot;; mso-bidi-font-family: &quot;&quot;; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">个小时,如果轮船在静水中的速度是</span><span lang="EN-US" style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">10</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: &quot;&quot;; mso-hansi-font-family: &quot;&quot;; mso-bidi-font-family: &quot;&quot;; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">千米每小时,求</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">
                </span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: &quot;&quot;; mso-hansi-font-family: &quot;&quot;; mso-bidi-font-family: &quot;&quot;; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">水流的速度</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;"> .</span></p><p><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: &quot;&quot;; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">大家都来看看这道题,这是一道初中的数学题,不知道有没有人看出什么毛病.</span></p>

周昶 发表于 2007-10-12 11:04:27

<p>我自己先发表下见解 </p><p>假设水流速度是不变的情况下 方程应该是这样的<br/>5×(10-X)+5×(10+X)=48×2<br/>这道题根本就把水的逆流和顺流给忽略了&nbsp; 对我们现在的思维来说这道题完全是错误的题目</p>

fate_1234 发表于 2007-11-21 19:57:00

<p>假设水流速度是不变的情况下 方程应该是这样的<br/>48/(10-X)+48/(10+X)=10</p><p>X=2</p><p></p>

筱枫 发表于 2007-11-21 23:39:50

<p>同意3楼的。楼主出的题目自己的解法都是错误的,真不知道以前你是这么考过来的o(∩_∩)o...哈哈</p>

dcgg 发表于 2007-11-23 10:12:07

<p>三楼正解</p>

xiaoz 发表于 2007-11-23 13:56:40

<p>顺流和逆流所用的时间明显不一样的</p><p>你把水的顺流和逆流给忽略了犯了先入为主的错误 </p>

猪头还是猪头 发表于 2007-11-23 16:01:52

<p>题目没有什么问题,怀疑楼主的数学水平,如何度过重重考关(北京的就算了,及格的水平)</p>

dqsvictor 发表于 2007-11-23 16:30:02

严重同意楼上几位的意见,LZ理解错了.

czong1972 发表于 2007-11-23 20:25:55

常识性错误!

clsong1998 发表于 2007-11-24 14:28:12

脱离实际

船到码头后总是要卸货或卸人,这里没有考虑进去这个时间以及船掉头时间。此外,还有的话就是船未必是走直线的!
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