LINWENMO
发表于 2003-7-19 12:49:00
300
sharesam
发表于 2003-12-12 16:51:00
以下是引用亮者亮也在2003-6-25 20:38:00的发言:
如果问的是跑过的距离的话应该是200米
如果问的是跑过的路程则应是214米,呵
距离起点也应该是100M啊。路程241应该是对的。
幻月离花
发表于 2004-2-14 21:53:00
设:通讯员到队伍首走的距离为100+s,列方程如下:
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">s/v</FONT></SPAN><SUB><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">队</SPAN></SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">=(100+s)/v</FONT></SPAN><SUB><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">人</SPAN></SUB><SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt"><?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p></SPAN></SUB>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><FONT face="Times New Roman"><SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt">100/</SPAN></SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt"> v</SPAN></FONT><SUB><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">队</SPAN></SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">=(2s+100)/ v</FONT></SPAN><SUB><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">人</SPAN></SUB><SUB><SPAN lang=EN-US style="FONT-SIZE: 22pt"><o:p></o:p></SPAN></SUB>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">得出</SPAN><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">s=70.7<o:p></o:p></FONT></SPAN>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">则通讯员来回路程</SPAN><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">=2s+100<o:p></o:p></FONT></SPAN>
<P class=MsoNormal style="MARGIN: 0cm 0cm 0pt"><SPAN style="FONT-SIZE: 22pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">得出</SPAN><SPAN lang=EN-US style="FONT-SIZE: 22pt"><FONT face="Times New Roman">241.4<o:p></o:p></FONT></SPAN>
yyygm
发表于 2004-2-15 12:20:00
200m
ximiga
发表于 2004-2-18 11:06:00
200米决对正确
maya007
发表于 2004-2-23 21:35:00
200
fisummer
发表于 2004-3-2 11:31:00
200m
justine
发表于 2004-3-6 17:17:00
241m,这道题并不复杂
jinpong
发表于 2004-3-7 22:52:00
设所求的距离为x,
两段时间分别为t1,t2;通讯员速度v1,队伍速度v2
t1=100/(v1-v2)
t2=100/(v1+v2)
100/v2=x/v1=t1+t2
得到x=100v2/v1=100v1(1/(v1+v2)+1/(v1-v2))
[此贴子已经被作者于2004-3-7 23:03:03编辑过]
随缘
发表于 2004-3-29 15:59:00
<P>200</P>